Question

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Answer 1

➡️ Let the three consecutive multiples of 3 be

x, x+ 3, x + 6.

According to the problem :

➡️ x + x + 3 + x + 6. = 867

➡️ 3x + 9 = 867

➡️ 3x = 858

➡️ x = 286

➡️ x + 3 = 286 + 3 = 289

➡️ x + 6 = 286 + 6 = 292

Answer 2

Answer:

$\blue{\huge{\bold{\boxed{\green{\boxed{\red{\underline{ANSWER}}}}}}}}$

given 3 consecutive multiples of 3

let x, x+3, x+6 be the multiples of 3

given sum of the 3 multiples is 867

x+x+3+x+6=867

3x+9=867

3x=867-9

3x=858

x=286

• therefore x=286
• x+3= 289
• x+6=292

Explanation:

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