Question

Answer it .

3u2–10u+3

find zeroes

Answer 1

Heya there

here is your answer

Answer 2

Answer:

$\displaystyle{Zeroes \ are \ 3 \ and \ 1/3}$

Explanation:

Given :

$\displaystyle{p(x)=3u^2-10u+3}$

We have to find zeroes

Let first factorize it

By splitting mid term method

$\displaystyle{p(x)=3u^2-10u+3}\\\\\displaystyle{p(x)=3u^2-9u-u+3}\\\\\displaystyle{p(x)=3u(u-3)-(u-3)}\\\\\displaystyle{p(x)=(u-3)(3u-1)$

Now for zeroes of p ( x )

$\displaystyle{p(x)=(u-3)(3u-1)=0}\\\\\displaystyle{u-3=0 \ or \ 3u-1=0}\\\\\displaystyle{u=3 \ or \ u = 1/3$

Thus we get zeroes.