Question

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Answer 1

Answer:

here's ur answer mate!!!!

Explanation:

Let the volume of the cube be V and the fraction of cube outside water be f.

Thus, volume of ice inside water = volume of water displaced =(1−f)V

Under equilibrium,

Weight of ice = Weight of water displaced

⟹Vρiceg=(1−f)Vρwaterg

⟹(1−f)=109

⟹f=101

Thus, the percentage of volume outside water =10%

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