Question

answer it as soon as possible

Answer 1

All logarithms can be expressed in an exponential form.
$if \: log_{a}(x) = b \\ then \: {a}^{b} = x$
We will use this in the sum above
$log_{b}(b) = 1 \\ converting \: to \: exponential \: fom \\ {b}^{1} = b$
Since any number raised to 1 is the number itself, the first equation is proved.

$log_{b}(1) = 0 \\ converting \: to \: exponential \: form \\ {b}^{0} = 1$
Since any number raised to 0 is equal to 1, the second equation is also proved.