Question

Answer it as soon as possible pls!!​

Answer 1

first of all

the volume of well=πr²h

= 22/7×3/2×3/2×14

= 11×3×3

= 99m cube

now,the volume of embankment = 22/7×h[(1.5+4×1.5+4)-1.5×1.5]

99=22/7×h(5.5×5.5-2.25)

99=22/7×h(30.25-2.25)

99=22/7×h×28

99=88h

99/88=h

9/8=h

h=1.125m

ans

Answer 2

A well of diameter 3 m is dug which is 14 m deep.

We can say that the well is cylindrical.

Volume of the well = $\pi r^{2} h$

Volume = $\pi *\frac{3}{2} *\frac{3}{2} *14$

             $= 99$ m³

The same mud is used to form a circular ring of width 4 m

A circular ring can be viewed as two concentric cylinders. The volume of the ring is actually the difference in the volumes of both the complete cylinders.

If  R is the radius of larger cylinder and r is radius of smaller cylinder,

Volume of ring = $\pi R^2h - \pi r^2h$

                         = $\pi h(R^2-r^2)$

R = $\frac{3}{2} +4=\frac{11}{2}$ m

r = $\frac{3}{2}$ m

Hence volume of ring = $\pi h[(\frac{11}{2})^2 -(\frac{3}{2})^2]$

                                     = $88h$ m³

Volume of well = Volume of ring

99 = 88h

$h = \frac{9}{8} = 1.125m$

HOPE THIS HELPS!!