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Dimensions: 5cmX2cmX1cm
Number of chocolates: 10
In order to find the area of wrapping paper required, we need to find the total surface area(TSA) of the chocolates
TSA of 1 chocolate=2(lb+bh+lh)
=2[(5 X 2)+(2 X 1)+(5 X 1)]
=2[10+2+5]
=2[17]= 2 X 17= 34sq. cm
Hence, TSA of 10 chocolates=34 X 10
=340sq. cm
Area of wrapping paper required=340sq. cm
Hope it helps<3
Pls mark as the brainliest if it does.
Number of chocolates: 10
In order to find the area of wrapping paper required, we need to find the total surface area(TSA) of the chocolates
TSA of 1 chocolate=2(lb+bh+lh)
=2[(5 X 2)+(2 X 1)+(5 X 1)]
=2[10+2+5]
=2[17]= 2 X 17= 34sq. cm
Hence, TSA of 10 chocolates=34 X 10
=340sq. cm
Area of wrapping paper required=340sq. cm
Hope it helps<3
Pls mark as the brainliest if it does.
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