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Solution :
Let y=xsinx
⇒logy=log(xsinx)
=sinx⋅logx
1ydydx=sinx⋅1x+logx⋅cosx
⇒dydx=y[sinxx+logx⋅cosx]
⇒dydx=xsinx[sinxx+logx⋅cosx]⋅
this is the answer
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