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Answers
In the given reaction
sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water
sodium carbonate + ethanoic acid → sodium ethanoate + carbon dioxide + water
We need to show that the law of conservation of mass is agreed in the above reaction.
Solution
Let us start from the reactant side
In the reactant side we have sodium carbonate and ethanoic acid
Mass of sodium carbonate=5.3g (given)
Mass of ethanoic acid=6g(given)
Now total mass before reaction that is mass of reactants = (5.3g + 6g) = 11.3g
Now let us check product side
Mass of carbon dioxide = 2.2g (given)
Mass of water = 0.9g (given)
Mass of sodium ethanoate = 8.2g (given)
Now total mass after reaction that is mass of products = (8.2g + 2.2g + 0.9g) = 11.3g
Conclusion
Total mass before reaction=total mass after reaction
Therefore the given observation is in agreement with the law of conservation of mass.
Hope helpful for you
Answer:
In the given reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water
sodium carbonate + ethanoic acid → sodium ethanoate + carbon dioxide + water
We need to show that the law of conservation of mass is agreed in the above reaction.
Solution:)
Let us start from the reactant side
In the reactant side we have sodium carbonate and ethanoic acid
Mass of sodium carbonate=5.3g (given)
Mass of ethanoic acid=6g(given)
Now total mass before reaction that is mass of reactants = (5.3g + 6g) = 11.3g
Now let us check product side
Mass of carbon dioxide = 2.2g (given)
Mass of water = 0.9g (given)
Mass of sodium ethanoate = 8.2g (given)
Now total mass after reaction that is mass of products = (8.2g + 2.2g + 0.9g) = 11.3g
Conclusion:)
Total mass before reaction=total mass after reaction
Therefore the given observation is in agreement with the law of conservation of mass.
Explanation:
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