answer it correct please..
Answers
Answer:
Solution:
Let l, b and h be the length, breadth and height of the box.
Bigger Box:
l = 25cm
b = 20 cm
h = 5 cm
Total surface area of bigger box = 2(lb+lh+bh)
= [2(25×20+25×5+20×5)]
= [2(500+125+100)]
= 1450 cm^2
Extra area required for overlapping 1450×5/100 cm2
= 72.5 cm^2
While considering all over laps, total surface area of bigger box
= (1450+72.5) cm^2 = 1522.5 cm^2
Area of cardboard sheet required for 250 such bigger boxes
= (1522.5×250) cm^2 = 380625 cm^2
Smaller Box:
Similarly, total surface area of smaller box = [2(15×12+15×5+12×5)] cm^2
= [2(180+75+60)] cm^2
= (2×315) cm^2
= 630 cm^2
Therefore, extra area required for overlapping 630×5/100 cm2 = 31.5 cm^2
Total surface area of 1 smaller box while considering all overlaps
= (630+31.5) cm^2 = 661.5 cm^2
Area of cardboard sheet required for 250 smaller boxes = (250×661.5) cm^2 = 165375 cm^2
Now, Total cardboard sheet required = (380625+165375) cm^2
= 546000 cm^2
Given: Cost of 1000 cm^2 cardboard sheet = Rs. 4
Therefore, Cost of 546000 cm^2 cardboard sheet =Rs. (546000×4)/1000 = Rs. 2184
Therefore, the cost of cardboard required for supplying 250 boxes of each kind will be Rs. 2184.
Step-by-step explanation:
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