Question

answer it correct please... ​

Answer 1

Height of cylinder= 1 m

Base diameter of cylinder = 140 cm = 1.4 m

Radius= diameter /2 = 1.4/2 = 0.7 m

What to find?

area of metal sheet required

Area of metal sheet required is the same as the area of closed cylindrical tank

Therefore, Area of metal sheet = 2πr^2 + 2πrh

$= 2\pi(0.7) ^{2} + 2\pi(0.7)(1) \\ = 2\pi(0.49) + 1.4\pi \\ = 0.98\pi + 1.4\pi \\ = 2.38\pi \\ = 5.38 \: {m}^{2}$

Area of metal sheet required = 7.48 m2

Answer 2

Answer:

Solution:

Let h be the height and r be the radius of a cylindrical tank.

Height of cylindrical tank, h = 1m

Radius = half of diameter = (140/2) cm = 70cm = 0.7m

Area of sheet required = Total surface are of tank = 2πr(r+h) unit square

= [2×(22/7)×0.7(0.7+1)]

= 7.48

Therefore, 7.48 square meters of the sheet are required.