Question

Answer it correctly...✌
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Answer 1

Question:-

• The third and sixth term of a GP are 12 and 96, find the sequence.

Solution:-

Let the first term be a

Therefore,

nth term=$\sf ar^{n-1}$

Or,

3rd term=$\sf ar^{2}$

6th term=$\sf ar^{6-1}=ar^{5}$

So,

$\sf 12 = a {r}^{2}$

$\sf 96 = a {r}^{5}$

Or,

$\sf \implies \frac{96}{12} = \frac{a {r}^{5} }{a {r}^{2} }$

$\sf \implies 8 = {r}^{3}$

$\sf \implies r = 2$

Now,

$\sf 12 = a {r}^{2}$

Or,

$\sf a = 12 \div 4$

$\sf \implies a = 3$

So,

$\sf a = 3$

$\sf ar = 6$

$\sf a {r}^{2} = 12$

So, the sequence will be,

3 6 12 24 48 96 192...

Answer:-

The sequence is 3 6 12 24 48 96 192....

Hope it helps you..

Answer 2

So your final answer is-

GP- 3,6,12,24...

i hope you get your answer

thnx for asking

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