Question

answer it correctly ​

Answer 1

Given to find the value of :-

$\bigg \{5 \bigg(8 {}^{ \frac{1}{3} } + 27 {}^{ \frac{1}{3} } \bigg) {}^{3} \bigg \} {}^{ \frac{1}{4} }$

S O L U T I O N :-

As we know that,

$8 = 2 {}^{3} \\ 27 = 3 {}^{3}$

$\bigg \{5 \bigg((2 {}^{3}) {}^{ \frac{1}{3} } + (3 {}^{3}) {}^{ \frac{1}{3} } \bigg) {}^{3} \bigg \} {}^{ \frac{1}{4} }$

$\bigg \{5 \bigg((2 {}^{ \not3}) {}^{ \frac{1}{ \not3} } + (3 {}^{ \not 3}) {}^{ \frac{1}{ \not3} } \bigg) {}^{3} \bigg \} {}^{ \frac{1}{4} }$

$\bigg \{5 \bigg((2 + 3 \bigg) {}^{3} \bigg \} {}^{ \frac{1}{4} }$

$\bigg \{5 \bigg(5 \bigg) {}^{3} \bigg \} {}^{ \frac{1}{4} }$

$\bigg \{5 \times 5 {}^{3} \bigg \} {}^{ \frac{1}{4} }$

$\bigg \{ 5 {}^{4} \bigg \} {}^{ \frac{1}{4} }$

$\bigg \{ 5 {}^{ \not4} \bigg \} {}^{ \frac{1}{ \not4} }$

$5 {}^{1}$

$= 5$

So, the required answer is 5

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