Question

Answer it correctly it is very urgent​

Answer 1

Answer:

both are not the zeroes of this polynomial

Step-by-step explanation:

$f( - \frac{1}{ \sqrt{3} } ) = 3 \times - \frac{1}{ \sqrt{3} } - 1 \\ f( - \frac{1}{ \sqrt{3} } ) = \sqrt{ - 3 } - 1 \\ \\f( \frac{2}{ \sqrt{3} } ) = 3 \times \frac{2}{ \sqrt{3} } - 1 \\ f( \frac{2}{ \sqrt{3} } ) = 2 \sqrt{3} - 1$

Answer 2

Answer:

so so sorrry .........