Question

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osmotic pressure of cacl2 and urea solution of the same concentration at the same temperature are respectively 0.605 atm and 0.245 atm. calculate vant hoff factor for cacl2​

Answer 1

Given :

osmotic pressure of CaCl$_2$ = 0.605 M

osmotic pressure of urea = 0.245 M

To find :

The van't hoff factor of CaCl$_2$ .

Solution :

Osmatic pressure , π = i * C * R * T

where , C is concentration

R is gas constant

T is temperature

and, i is van't hoff factor

for urea,

0.245 = 1 * C * R * T = C * R * T       .....(i)

as the concentration and the temperature is same , for CaCl$_2$ ,

0.605 = i * 0.245             {from (i) }

=> i = 2.469

The van't hoff factor of CaCl$_2$  is 2.469 .

Answer 2

Your answer in attachment!

Explanation:

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