Answer it don't Spam otherwise it will be reported.
Attachments:
Answers
Answered by
21
Explanation:
Since here gases of different volume and pressure are mixed in a vessel of 1L we should focus on the parameter Which will Not change after mixing i.e.no.of moles
:-we know,
PV=nRT
Then further implies that: n=PV/RT
Now for H2,
No.of moles=PV/RT
Pressure (P)=0.8 bar
Volume (V)=0.5L
Moles of H2=0.8×0.5/RT
Now For O2,
Pressure (P)=0.7bar
Volume (V)=2L
No.of moles of O2=PV/RT
=0.7×2/RT=1.4RT
Total no.of moles=0.4/RT+1.4/RT=1.8/RT
Total pressure=n'RT/V' Here,n is total no. of moles=1.8/RT
V is total volume=1L
Total pressure=1.8/RT
=Total pressure=1.8/RT×RT/1=1.8 atm.
Hence,the total pressure of the gaseous mixture will be 1.8 atm.
hope it will help you
Answered by
0
Answer:
1.79 bar
Explanation:
P×1=(n
H 2 +n O 2 )
×0.0821×300
⇒P=(0.016+0.056)×0.0821×300
⇒ P=1.79bar
mark me as brainliest.
Similar questions
Geography,
2 months ago
India Languages,
2 months ago
Math,
2 months ago
Biology,
10 months ago
Social Sciences,
10 months ago
Math,
10 months ago