Question

ANSWER IT FAST ⬆️⬆️⬆️
10TH CLASS
REFRACTION OF LIGHT AT CURVED SURFACES

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Answer 1

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✤ Required Answer:

⚡GiveN:

• The above is a concave mirror
• Object is placed at a distance 60 cm
• Focal length of the mirror = 20 cm

⚡To FinD:

• Image distance and position....?

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✤ How to solve?

When we are given or provided with any two of the image distance, focal length and object distance, we can find the third by using the mirror formula, which is given by:

$\large{ \cdot{ \boxed{ \rm{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }}}}$

Here,

• v = Image distance
• u = Object distance
• f = Focal length

Sign Convection,

CONCAVE MIRROR

• Focal length = negative

CONVEX MIRROR

• Focal length = positive

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✤ Solution:

We have,

• u = -60 cm

[ The image is at opposite direction of light ray ]

• f = -20 cm

[ The focal length of concave mirror is negative ]

By using mirror formula,

➝ 1/v + 1/u = 1/f

➝ 1/v + 1/-60 = 1/-20

➝ 1/v = -1/20 + 1/60

➝ 1/v = -3 + 1 /60

➝ 1/v = -2/60 = -1/30

➝ v = -30 cm

☃️ Image distance = -30 cm

[ Image distance is negative 30 cm, where negative sign indicates at front of the mirror and opposite to the direction of light ray. ]

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Answer 2

Answer:

Rey emaipoyaave chinnu