answer it fast ........
Answers
Answer:
Area of shaded portion = 56 cm^2
Step-by-step explanation:
I cannot see the shaded part but analysing the question, I think the question asks to find the area between the between where the 4 circles touch externally inside the square.
Let the point where circles A and B intersect be E, B and C intersect be F, C and D intersect be G and where D and A intersect be H.
Area of shaded portion = Area of square - Area of ( AEH + BEF + CFG + DHG) ---------------------(1)
Area of square :-
side of square = AE + BE
= 14 + 7
= 21 cm
Area = side^2
=> Area of square = 441 cm^2
Area of AEH :-
= πr^2 x 90 degrees/360 degrees ( since angle BAD = 90 degrees because all angles of a square are = 90 degrees)
= 1/4 πr^2 ( In other words, AEH is a quadrant)
= 1/4 x 22/7 x 7 x 7
= 38. 5 cm^2
Since radius of circle C = radius of circle A = 7cm and both are quadrants,
Area of AEH = Area of CFG = 38.5 cm^2
Area of BEF :-
= 1/4πr^2
= 1/4 x 22/7 x 14 x 14
= 154 cm^2
Since radius of circle D = radius of circle B and both are quadrants,
Area of BEF = Area of DHG = 154 cm^2
Combined area of AEH, CFG, BEF and DHG = 38.5 + 38.5 + 154 + 154
= 385 cm^2
=> Area of shaded portion = 441 - 385 [ By ( 1) ]