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I think you didn't mention the full question. Was it to find a and b?
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Given equation is,
√28 - 6√3 = √3a + b
By expanding equation,
√ 1 + 27 - 6√3 = √3a + b
⇒ √(1)2 + (3√3)2 - 2 x 3√3 = ⇒ √3a + b
⇒ √(1 - 3√3)2 = √3a + b
⇒ 1 - 3√3 = √3a + b
On comparing the left and right side equation, we get,
a = -3, b = 1
∴ a + b = -3 + 1 = - 2
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