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Step-by-step explanation:
From given figure ,
angle ADE = angle B
To prove : triangle ABC ~ triangle ADE and to find DE
Given :
AD = 3.8 cm , AE = 3.6 cm , BE = 2.1 cm and BC = 4.2 cm
Now in triangle ADE and triangle ABC ,
angle ADE = angle B ( given )
angle A = angle A ( common )
So , triangle ABC ~ triangle ADE ( By AA )
Again ,
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Angle ADE = Angle B
To Proof : Triangle ABC ~ Triangle ADE and to find DE
Given :- AD = 3.8cm, AE = 3.6cm BE = 2.1 cm and BC = 4.2 cm
Now in triangle ADE and Triangle ABC
Angle ADE = Angle B {Given }
Angle A = Angle A { Common }
So, triangle ABC~ Triangle ADE
Again
AD/AB = DE/BC
AD/AE + EB = x/4.2
3.8/3.6+2.1 = x/4.2
x= 2.8cm
DE = 2.8 cm
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