Question

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Answer 1

Answer:

Let x=4a-3b, y=b-3a, z=2b-a

On adding x+y+z=0

therefore, x³+y³+z³=3xyz

Substituting x,y,z values we get

(4a-3b)³+(b-3a)³+(2b-a)³=3(4a-3b)(b-3d)(2b-a)

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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