Question

answer it fast and i will definitely mark it as brainliest

Answer 1

Soln-

a¹/³ + b ¹/³ + c ¹/³ = 0

=» (a¹/³)³ + (b ¹/³)³ + (c ¹/³)³

. . . .=3(a¹/³)(b¹/³)(c¹/³)

=» a + b + c = 3a¹/³b¹/³c¹/³

Answer 2

⭐Solution⭐

✏given here

³√a + ³√b + ³√c = 0......(1)

✏Find here

(a+b+c)³ = ❓

We know ,

(x+y+x)³= (x³+y³+z³)+3(x+y)(y+z)(z+x)

So,

by (1),

(³√a + ³√b +³√c)³

= (³√a)³ + (³√b)³ + (³√c)³ + 3(³√a + ³√b)(³√b + ³√c)(³√c + ³√a)

= (a+b+c) + 3(³√a + ³√b)(³√b + ³√c)(³√c + ³√a)........(2)

keep value by (1)

(0) = (a+b+c) + 3(³√a + ³√b)(³√b + ³√c)(³√c + ³√a)

=> (a+b+c) + 3(³√a + ³√b)(³√b + ³√c)(³√c + ³√a) = 0

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✏Hopes it's right and helps u.

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