Question

answer it fast and i will mark as brain list

Answer 1

Answer:

${ \sec }^{2} \alpha + { \tan }^{2} \alpha = 7$

$(1 + { \tan }^{2} \alpha ) + { \tan }^{2} \alpha = 7$

$1 + 2 { \tan }^{2} \alpha=7$

$2 { \tan}^{2} \alpha=7 - 1$

$2 { \tan}^{2} \alpha=6$

${ \tan}^{2} \alpha=3$

$\tan\alpha = \sqrt{3}$

$\tan \alpha = \tan(60)$

$\alpha = 60$