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Answer: First term = 10, 20th term = 200
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Step-by-step explanation:
SN = N/2(2A+(N-1)D)
S14 = 7(2A +13D)=1050
-> 2A + 13D = 150(I)
Also, S28 - S14 = 3010
14(2A+27D) - 7(2A + 13D) = 3010
7[4A + 54D - 2A - 13D] = 3010
2A + 41D = 430(II)
Solving I,II-
D = 10
A=10
-> A1 = 10
-> A20 = A1 + 19D = 200
FIRST TERM=10, 20TH TERM=200
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