Question

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Answer 1

Answer:

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Answer 2

Answer:

current through 10Ω resistor = 2 amp.

current through 20Ω resistor = 1 amp.

Explanation:

Let current through 10Ω resistor be $I_{1}$.

And current through 20Ω resistor be $I_{2}$.

Now, $I_{1}+I_{2}=3amperes=I$

And it is known that current is inversely proportional to resistance.

Therefore, $I_{1}=\frac{IR_{2}}{R_{1}+R_{2}}$        [$R_{1}$ = 10Ω and $R_{2}$ = 20Ω]

             => $I_{1} = \frac{(3)(20)}{10+20}$

             => $I_{1}=2 amperes.$

Therefore, $I_{2} =I-I_{1} = 1amperes.$