Question

Answer it fast...
I will mark first answer as the Brainliest one...​

Answer 1

Given :

Potential difference when current is 4 A = 60 V

To find :

Current drawn when potential difference rises to 120 V .

Solution :

Long method :

When I = 4 A , V = 60 V

Using Ohm's law ,

V = IR

R = V/I

R = 60/4

R = 15 Ω

Now , when V rises to 120 V

V = 120 V , R = 15 Ω

Again using Ohm's law ,

V = IR

I = V/R

I = 120/15

I = 8 A

Short method

Ohm's law states that :

$\tt V \propto I$

When V = 60 , I = 4

When V = 120 = 2 × 60 , current will also be doubled

$\therefore$ I = 2×4 = 8 A

Answer 2

Answer:

Answer for the problem is given.