Math, asked by komalDeshmukh, 11 months ago

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Answers

Answered by utkarshvikas
1

Step-by-step explanation:

area of triangle AGB=1/2(b×h)

=1/2(3×2)

=3 cm^2

area of tri. AHF=1/2(4×4)

=8 cm^2

area of tri. DEJ=1/2(2×2)

=2 cm^2

area of tri.ICD=1/2(5×3)

=7.5 cm^2

area of trapezium BGIC=1/2( sum of parallel side)×h

=1/2(5+3)×4

=16 cm^2

area of trapezium HFEJ

=1/2(4+2)×3

=9 cm^2

total area=(3+8+2+7.5+16+9)cm^2

=45.5 cm^2

hope it help you

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