Math, asked by gomalp, 6 months ago

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Answered by kbpatel2751
1

Answer:

Step-by-step explanation:

as 30 students are passed in both of the subjects so,

let, A be the students passed in hindi and let, B be the students passed in maths

p(A) = 60 - 30 = 30

p(B) = 40 - 30 = 10

p(A∩B) = 30 students who passed in both the subjects

the number of students who passed in at least one subject = p(A) + p(B) + p(A∩B)

= 30 + 10 +30

= 70

Answered by priyomrabhadas
4

Given :-

  • In an exam,

  • 60 Students passed in Hindi,

  • 40 students passed in Math,

  • 30 Students passed in both the subjects.

To Find :-

  • Find the number of students who passed at least in one of the subjects.

Solution :-

  • Required to find the Students who at least passed in one of the subject's.

  • Student passed in :

⇒ Hindi - 60 passed

⇒ Math - 40 passed

⇒ Both the subject - 30

  • ∴ Passed at least One of the subjects = 60 + 40 - 30

                                                                        =  ( 60 + 40 ) - 30

                                                                         = 100 - 30

                                                                          = 70

Ans. The Number of students passed at least one of the subjects = \sf{\underline{\ 70}

{\huge{\boxed{\sf{\ Hence~stated}}}}

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