Question

answer it fast please​

Answer 1

Answer:

the frequency of revolution of the particle is 60.r.p.m ie (60÷60)=1r.p.s so n=1

time period will be 1/n=1/1=1 seconds

so w=2×π×1

or w=2π

thus the linear speed will be

v=w×r

the centripetal acceleration will be equal to mw2r

where by replacing the value of m,w,r one can deduce the value of the centripetal acceleration

so centripetal acceleration will be 8m(π^2) m/squ.. sec

I hope my answer will help you my dear friend