Question

!!!!!answer it fast please​

Answer 1

$Cos(270\degree - \theta) + sin( 180\degree - \theta) = \underline {\red {0}}$

Explanation:

We know that,

• Cos(270°- A) = -sinA
• sin(180° - A) = sinA

$\red{ Cos(270\degree - \theta) + sin( 180\degree - \theta)}\\= -sin\theta + sin \theta \\= 0$

••♪

Answer 2

Explanation:

Cos(270°−θ)+sin(180°−θ)=

0

Explanation:

We know that,

Cos(270°- A) = -sinA

sin(180° - A) = sinA

\begin{lgathered}\red{ Cos(270\degree - \theta) + sin( 180\degree - \theta)}\\= -sin\theta + sin \theta \\= 0\end{lgathered}

Cos(270°−θ)+sin(180°−θ)

=−sinθ+sinθ

=0