Question

Answer it fast please​

Answer 1

first put x= -1 in q(x)

q(-1)= 3(-1)^2 - 7(-1) - 8 = 3 + 7 - 8 = 2

now put x = q(-1) , i.e., x = 2 in p(x)

p(q(-1))= (2)^3 + 3(2) - 2(2)^2 - 6

= 8 + 6 - 8 - 6 = 0

hence q(-1) is a zero of p(x)

Answer 2

Step-by-step explanation:

p(x) =x4+3x-2x2-6

q(x)=3x2-7x-8

now

q(-1)= 3(-1)2-7(-1)-8

3+7-8

=2

we have to prove that p(2) is the zero of p(x)

p(x) = x4-2x2+3x-6

(2)4-2(4)2+3(2)-6

=0

hence proved