Question

answer it fast please.....and correctly​

Answer 1

Answer:B

Step-by-step explanation:

As, 128=2^7

And 16=2^4

So, 2^15+4n

Answer 2

Solution :-

⟿ 128 * 16^(n + 2)

⟿ 2^7 * (2^4)^(n + 2)

using (a^m)^n = a^(m * n) Now,

⟿ 2^7 * 2^{4(n+2)}

⟿ 2^7 * 2^(4n + 8)

using a^m * a^n = a^(m + n) Now,

⟿ 2^(7 + 4n + 8)

⟿ 2^(15 + 4n) (Ans.) (B)

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Extra :-

→ x^1 = x

→ x^0 = 1

→ x^(-1) = 1/x

→ x^m*x^n = x^(m+n)

→ x^m/x^n = x^(m-n)

→ (x^m)^n = x^(mn)

→ (xy)^n = x^n*y^n

→ (x/y)^n = x^n/y^n

→ x^(-n) = (1/x)^n

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