Answer it fast please.....calculate the number of atoms of oxygen present in 88g of CO2.what would be weight of CO. having same number of Oxygen atom
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Question:-
Calculate the number of atoms of oxygen present in 88g of CO2. What would be weight of CO. Having same number of Oxygen atom?
Solution:-
No of oxygen atoms in CO2 = 2× 88/44 × Avogadro's constant
No of oxygen atoms = weight of CO/28 × Avogadro's constant
No of oxygen atoms in CO2 = no of oxygen atoms in CO
2 × 88/44 = weight of CO/28
Weight of CO = 112 g
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