Question

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Answer 1

Answer:

I have answered 1, 2,3

now

$4) \: \: \: \: {x}^{2} + \frac{3}{2} x - \frac{9}{2} = 0$

$5) \: \: \: \: \: \sqrt{3} {x}^{2} - 6x - 2x + 4 \sqrt{3} = 0$

$= \sqrt{3} x(x - 2 \sqrt{3} ) - 2(x - 2 \sqrt{3} ) = 0$

$= ( \sqrt{3} x - 2)(x - 2 \sqrt{3} ) = 0$

$= x = \frac{2}{ \sqrt{3} } \: \: \: \: and \: \: \: \: 2 \sqrt{3}$