Question

answer it fast please plz​

Answer 1

We know that 4.2626 lies between 4 and 5.

So, divide the gap between 4 and 5 into ten parts.

So, we get 4,4.1,4.2,4.3,4.4,4.5,4.6,4.7,4.8,4.9,5

Now, if we see closely, we can observe that 4.2626 lies between 

4.2 and 4.3.

So, divide the gap between 4.2 and 4.3into ten parts.

We get 4.2,4.21,4.22,4.23,4.24,4.25,4.26,4.27,4.28,4.29,4.3

Now, if we observe more closely 4.2626lies between 4.26 and 4.27.

Divide the gap between 4.26 and 4.27 into ten parts.

So, we get 

4.26,4.261,4.262,4.263,4.264,4.265,4.266,4.267,4.268,4.269,4.27.

Now, if we see closely, we can observe that 4.2626 lies between 4.262 and 4.263.

Divide the gap between 4.262 and 4.263into ten parts.

So, we get

 

4.262,4.2621,4.2622,4.2623,4.2624,4.2625,4.2626,4.2627,4.2628,4.2629,4.263.

Answer 2

We consider wire is doubled on it means to fold the length of wire. It means its length will get half and area of cross section will get doubled. Thus, R' = p' l'/A' = p (l /2) ÷ 2A = !/4 (p l / A) = 1/4R = 1/4× 4 = 1Ω.