answer it fast pls i request
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Ans:8
Step-by-step explanation:
(x+y)
3
−(x−y)
3
−6y(x
2
−y
2
)=ky
3
⇒ [(x+y)
3
−(x−y)
3
]−6y(x
2
−y
2
)=ky
3
We know, a
3
−b
3
=(a−b)(a
2
+ab+b
2
)
⇒ 2y(x
2
+2xy+y
2
+x
2
−y
2
−x
2
−2xy+y
2
)−6y(x
2
−y
2
)=ky
3
⇒ 2y(3x
2
+y
2
)−6y(x
2
−y
2
)=ky
3
⇒ 6x
2
y+2y
3
−6x
2
y+6y
3
=ky
3
⇒ 8y
3
=ky
3
∴ k=8
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