Physics, asked by lathikasanthamurthy, 7 months ago

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Answered by akshay4u
1

Answer:

Ans of the Q.1.) The image is formed behind the lens at 2f or the center of curvature.

It is real, inverted, and the same size as the object.

Ans of the Q.2.) the size or age is 4.5cm.

Explanation:

Q.1.

ans.-

These types of problems can all be solved using the lens (or mirror) equation.

1/20 +1/q= 1/10

q=20 cm

The image is formed behind the lens at 2f or the center of curvature.

It is real, inverted, and the same size as the object.

Q.2.

ans.-

Height of object, h = 3cm.

focal length,f = -15cm.

object distance, u = 10cm.

by the lens formula,

1/f 1/v- 1/u

1/-15 1/v - 1/-10

1/v 1/-15 +1/10

1/V=-3+1/-30

1/v=-2/-30

1/v 15cm.

size of object,

m h'/h = -v/u

h'= 3x-15/-10

h'= 9/2

h' 4.5cm

so the size of object/image is 4.5cm.

Answered by latadesai2848
2

Answer:

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