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43
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Let the original number be = 10x + you
sum of the digit = x + y = 7 [Given] ..... (1)
The number is reversed then number will be
10y + x
If the number with the order of digits
reversed is 28 greater than twice the
unit digit of original number [Given]
=> 10y + x = 2y + 28
=> 8y + x = 28 ...... (2)
From equation (1) and (2) we get
=> -7y = -21
=> y = 3
put y = 3 in equation (1) we get
=> x + 3 = 7
=> x = 4
then, original number be = 10x + y
=> 10 (4) + (3)
=> 43 = answer
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