Question

Answer it fast!! Whoever answer it fast I will mark brainiest!
If the number of molecules in the given sample of sulphur dioxide is 3.011×10^23. Calculate the following:-
1) The number of moles in the given sample.
2) Mass of sulphur dioxide
3) Number of oxygen atoms in the given sample.

Answer 1

a).6.022 x 10 23 molecules of SO 2 = 1 mole of SO2
So, 3.011 x 10 23 molecules of SO 2 = (1/6.022 x 10 23 ) x 3.011 x 10 23 mole of SO2 = 0.5 moles of  SO2

b). 1 mole of SO2 = 32 + 2 x 16 = 64 gm
So, 0.5 mole of sample of ​ SO2 = 64 x 0.5 = 32 gm

c). Mass of oxygen in  64 gm = (32 / 64)  x100 = 50 %
hence, mass of oxygen atoms in given sample (32 gm) = 32 x 50/100 = 16 gm

Answer 2

Explanation:

a).6.022 x 10 23 molecules of SO 2 = 1 mole of SO2

So, 3.011 x 10 23 molecules of SO 2 = (1/6.022 x 10 23 ) x 3.011 x 10 23 mole of SO2 = 0.5 moles of SO2

b). 1 mole of SO2 = 32 + 2 x 16 = 64 gm

So, 0.5 mole of sample of SO2 = 64 x 0.5 = 32 gm

c). Mass of oxygen in 64 gm = (32 / 64) x100 = 50 %

hence, mass of oxygen atoms in given sample (32 gm) = 32 x 50/100 = 16 gm