Question

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Answer 1

Answer:

2) secx

Step-by-step explanation:

$\frac{d}{dx}(log(tanx+secx))$

= $\frac{\frac{d}{dx}(tanx+secx)}{tanx+secx}$

= $\frac{sec^2x +secxtanx}{tanx+secx}$

= $\frac{secx(secx+tanx)}{tanx+secx}$

= secx

Answer 2

Answer:

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