Question

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Answer 1

Answer:

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Answer 2

Answer:

given:

x+1/x = 3

identity -

(a+b)³ = a³+b³+3ab(a+b)

(x+1/x)³ =

x³ +1/x³ +3(x × 1/x) (x+1/x)

by putting the values.

(3)³ = x³+1/x³+3(3)

27 = x³+1/x³+9

x³+1/x³ = 27-9

= 18

identity -

(a+b)² = a²+b²+2ab

(x+1/x)² = x²+1/x² +2(x × 1/x)

by putting values

(3)² = x² +1/x² +2

x²+1/x² = 9-2

= 7

(x³+1/x³) (x²+1/x²)

= x³(x²+1/x²) +1/x³(x²+1/x²)

= x⁵ +x +1/x +1/x⁵

x⁵ +1/x⁵ +(x+1/x)

is also equal to

(18 ×7) we just found the values....

= 126

x⁵+1/x⁵ +(x+1/x) = 126

putting value of x+1/x

x⁵+1/x⁵ +(3) = 126

x⁵+1/x⁵ = 126-3

= 123 (answer)