Question

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Answer 1

Answer:

sin a + sin b = 2

we know that sin 90° = 1

sin 90 + sin 90 =

1+1 = 2

it satisfies.

and thus ,

a = b = 90

a-b =

90-90

= 0 (answer)

hope it helps¡¡

Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

FORMULA TO BE IMPLEMENTED

We know that for any angle

$\theta$

$- 1 \leqslant sin \theta \: \leqslant 1$

So the maximum value of Sine of an angle is 1

TO DETERMINE

$A - B \: \: when \: \: SinA + Sin B = 2$

CALCULATION

It is given that

$SinA + Sin B = 2$

Since the maximum value of Sine of an angle is 1

So

$SinA = 1 \: \: \: and \: \: \: Sin B = 1$

So

$\displaystyle \: SinA =Sin \frac{\pi}{2} \: \: \: and \: \: \: Sin B = Sin \frac{\pi}{2}$

So

$\displaystyle \: A = B = n\pi + {( - 1)}^{n} \frac{\pi}{2} \: \: where \: \: n \in \mathbb{Z}$

Hence

$\displaystyle \: A - B = 0$