Question

Answer it guys..,..​

Answer 1

Answer:

1)B

2)A

3)C

4)C

5)D

6)B

7)D

8)

9)

10)

11)

12)

13)

14)

15)

16)

17)

Answer 2

suppose the angles be equal to 3x and 2x

\boxed{ \sf \orange{ we \: have \: ardjacent \: angles \: of \: a \: parallelogram \: = 180}}

wehaveardjacentanglesofaparallelogram=180

\begin{lgathered}\begin{gathered}\\ \sf \underline{ \green{putting \: all \: values : }}\end{gathered}\end{lgathered}

puttingallvalues:

\begin{lgathered}\begin{gathered}\: \\ \sf \to \: 3x + 2 x = 180\: \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \:5x = 180 \\ \\ \: \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \frac{180}{5} \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \cancel{ \frac{180}{5} } \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \purple{x = 36}\\\\\end{gathered}\end{lgathered}

→3x+2x=180

→5x=180

→x=

5

180

→x=

5

180

→x=36

\begin{lgathered}\begin{gathered}\sf \to \: 3x \\ \sf \to \: 3 \times 36 \\ \sf \to \red{108 }\\ \\ \\ \sf \to \: 2x \\ \sf \to \: 2 \times 36 \\ \sf \to \orange{72} \\\end{gathered}\end{lgathered}

→3x

→3×36

→108

→2x

→2×36

→72