answer it guys, two times I've skipped to upload the attachment ...
This time , plz do answer...☝☝☝
Attachments:
ritesh1223:
lagta hain
Answers
Answered by
2
Here is your answer......
In triangle ABP and triangle ACQ
i)Angle BOY = Angle COX (vertically opposite angles)
ii)XY = XY (common)
iii)Angle XAY = Angle XAY (common)
Therefore, triangle ABP congruent triangle ACQ(ASA)
Therefore, Area of triangle ABP = Area of triangle ACQ (Congruent triangles have equal area)Proved..
Hope you like it....
Mark as brainliest....
In triangle ABP and triangle ACQ
i)Angle BOY = Angle COX (vertically opposite angles)
ii)XY = XY (common)
iii)Angle XAY = Angle XAY (common)
Therefore, triangle ABP congruent triangle ACQ(ASA)
Therefore, Area of triangle ABP = Area of triangle ACQ (Congruent triangles have equal area)Proved..
Hope you like it....
Mark as brainliest....
Answered by
0
dbbdjsjdjjr my ehsbndnsnsmsmsmslskkdjtvb
Similar questions