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750 m is the answer
Let the speed of sound be s
And the speed of sound is same for both events...
By which we can say that
2l /t = s
Where l is distance between cliff and source and t is the time of echo...
So, the first case will be
2l/4 = s
And second case will be
2l-150/3.6 = s
Equating both equation
2l/4=2l -150/3.6
7.2l = 8l - 600
600 = 0.8l
hence l = 750m
Hope it helped
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