Question

answer it....if 6x=secA and 6/x=tanA, find the value of 9(x²-1/x²)......​

Answer 1

Answer:

this I am not studied in previous class

Answer 2

Answer:

secA = 6x

TanA = 6/X

Property ; Sec²A - Tan²A = 1

Applying this property to our given values

(6x)² - (6/x)² = 1

36x² - 36/x² = 1

36(x² - 1/x²) = 1

Dividing both sides of the eq. by 4

9(x² - 1/x²) = 1/4

So Ur answer 1/4

Plzzz mark brainliest :)