Question

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Answer 1

Answer:

a = +- 1

Step-by-step explanation:

The given quadratic equation is ax² + bx + a = 0, and roots are distinct.

Then find the value of a.

Here, a = a, b = 2 and c = a

As we know that D = b² - 4ac

Putting the value of a = a, b = 2 and c = a, we get

(2)² - 4 × a × a

4 - 4a²

The given equation will have real and distinct roots, if D > 0

4 - 4a² = 0

4a² = 4

a² = 4

4

a² = 1

Taking square roots,

a = √1

= +- 1

Therefore, the value of a = +- 1.

Answer 2

Answer:

option A

Step-by-step explanation:

the given equations is ax^2+bx+a=0,and roots are distinct

then find value of a

here,a=a,b=2 and, c=a

as we know that D=b^2-4ac

putting the value of a =a,b=2 and , c= a

= (2)^2-4*a*a

=4-4a^2

the given equation will have real and distinct roots, if d greater than 0

4-4a^2=0

4a^2=4

a^2=4/4

a=√1

a=+-1

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