Question

answer it immediately as i am in need​

Answer 1

Step-by-step explanation:

∠BOC=180°-80°(AC is a straight line)

∠BOC=100

i) ∠BEC= ∠BOC/2 (angle at centre is twice angle at circumference)

=100°/2

=50°

ii) ∠OCB=∠OBC (OB=OB Radius of circle)

=(180-100)/2

=80/2

=40

∠BEC=∠DCE(Alternate angles)

therefore,∠BCD=50+10+40=100°

iii)∠CED= 180°- 100°=80°( opposite angles in a cyclic quadrilateral are supplementary