Physics, asked by dnavneetk9549, 10 months ago

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a person sitting on the top of a tall building is dropping balls at regular intervals of one second.Find the position of 3rd, 4th and 5th ball when the 6th ball is being dropped.

Answers

Answered by sanjeevaarav910
1

Answer:

the positions of the 3rd 4th and 5th ball are 45 m , 20 m & 5 m below the top of tower when 6th ball is being dropped.

Explanation:

A person sitting on the top of a tall building is dropping ball at regular intervals of one second.Find the positions of the 3rd 4th and 5th ball when the 6th ball is being dropped.

when the 6th ball is being dropped.

5th ball has travelled for 1 sec

4th Ball for 2 sec

3rd Ball for 3 sec

S = ut  +(1/2)at²

u = 0 dropped  

a = g = 10 m/s²

t = 1 , 2 , 3

Distance Covered in 1 Sec =  (1/2)10*1² = 5 m

Distance Covered in 2 Sec =  (1/2)10*2² = 20 m

Distance Covered in 3 Sec =  (1/2)10*3² = 45 m

the positions of the 3rd 4th and 5th ball are 45 m , 20 m & 5 m below the top of tower when 6th ball is being dropped.

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