Question

answer it is urgent please right now

Answer 1

Solution :

It is given that ,

a + b = 10 ----( 1 )

a² + b² = 58 ----( 2 )

We know the algebraic identity :

a² + b² + 2ab = ( a + b )²

=> 58 + 2ab = 10² [ from (1)&(2)]

=> 2ab = 100 - 58

=> 2ab = 42

=> ab = 42/2 = 21

ab = 21 ------( 3 )

Now ,

a³ + b³ = ( a + b )³ - 3ab(a+b)

= 10³ - 3 × 21 × 10

= 1000 - 630

= 370

Therefore ,

a³ + b³ = 370

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