Chemistry, asked by Mounikamaddula, 9 months ago

Answer it.... (No irrelevant answers)​

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Answers

Answered by Anonymous
1

Explanation:

As we know,

logK=logA−RTEa

2.9=logA−2.303R×769Ea ....(i)

1.1=logA−2.303R×667Ea ....(ii)

Subtracting eq. (ii) from in eq. (i)-

1.8=2.303REa[6671−7691]

1.8=2×667×769×2.303Ea×[769−667]

∴Ea=4.17×104calmol

Hope This will help you

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Mark me as brainliest if possible

Answered by Amrit111Raj82
4

Mark \: as \: brainliest........❤❤

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