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Explanation:
As we know,
logK=logA−RTEa
2.9=logA−2.303R×769Ea ....(i)
1.1=logA−2.303R×667Ea ....(ii)
Subtracting eq. (ii) from in eq. (i)-
1.8=2.303REa[6671−7691]
1.8=2×667×769×2.303Ea×[769−667]
∴Ea=4.17×104calmol
Hope This will help you
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